Every Strategy Has a Size It Stops Working At
Suneet Malhotra
Jul 09, 2026
My paper account caps any single position at ten thousand dollars of notional. At that size, in the large, liquid names it trades, my orders move the price by almost nothing, and the backtest is allowed to assume it. A fixed slippage per fill, the same number every time, subtracted and forgotten. That line is the most dangerous one in the whole system, because it is true right up until it is not, and nothing in the account tells me where the line sits.
The cost of a trade is not linear in its size
There are two ways to model what it costs to push an order into the market, and they disagree about the thing that matters.
The clean theoretical version is Kyle's 1985 model, in which price impact is linear in order flow: the price moves by some constant times the quantity you trade. Trade twice as much, move the price twice as far. It is tractable and it is wrong in a specific, well-documented direction.
The empirical version is the square-root law of market impact, and it is one of the most stable regularities in all of market microstructure. Measure the average price displacement caused by a large parent order, a metaorder worked over hours, and it scales not with the size but with the square root of the size. Roughly, the impact is proportional to the volatility of the name times the square root of the quantity divided by the daily volume, with a coefficient that empirical studies put on the order of one half to one. This shape holds across equities, futures, and other asset classes, across decades, across venues that share almost nothing else. It is about as close to a law as this field has.
The consequence hides in the exponent. If the price move to execute grows with the square root of size, then the cost per share also grows with the square root of size, and the total cost to trade grows faster than the size itself. Double your order and you do not double your cost per share. You multiply it by the square root of two, about one and four tenths. The tax is not a rate. It is a curve.
A constant-slippage backtest is a tangent line
Set the fixed slippage number next to that curve and its real nature is obvious. It is a tangent line. It is the value of the cost curve at exactly one point, the size I actually trade, extended flat in both directions as if the curve did not bend. Over a small neighborhood around that point the approximation is nearly exact, which is precisely the problem. At ten thousand dollars of notional in a mega cap, my quantity over daily volume is a rounding error, I sit deep in the flat part of the curve, and the constant is almost perfectly right. The approximation does not fail loudly. It works beautifully, at one size, and says nothing about any other.
That is what makes it seductive. A bad model that is wrong everywhere gets caught. A model that is exactly right in the region you test and quietly wrong everywhere else survives every check you run, because every check you run happens at the size where it is right.
The number I already published is a floor
I have an audit on this site from late April that measured what slippage actually cost across roughly two hundred real fills, and the answer was that it consumed close to forty percent of net profit. At the time I read that as an indictment of the execution. Read against the square-root law it is something worse. That forty percent was paid at my size, deep in the flat region, where the cost per share is the smallest it will ever be. It is not a fixed tax the strategy pays. It is the floor. The slippage I measured is the cheapest slippage this strategy will ever pay, and the only direction the number moves as the account grows is up, along a curve, faster than the account itself.
Which gives the honest definition of capacity. A strategy has a size at which its edge per trade and its impact per trade cross, and past that size it is a losing strategy running the exact same signal that made money at a tenth of the size. Nothing about the signal changed. Only the argument did.
The question with a missing argument
This is why does this strategy work is an ill-posed question. A Sharpe ratio, an expectancy, a win rate, measured at one level of assets, is a single point on a declining curve, not a property of the signal. Two funds can run an identical alpha and one prints money while the other bleeds, and the only difference between them is the size they run it at. The strategy is not good or bad. It is good up to a number and bad past it, and the number is set by the volatility and the volume of what it trades, not by how clever the signal is.
I wrote a few days ago that the closing auction offers cheap access to enormous size, on the condition that you are not the size everyone else is trading against. The square-root law is the price of being that size. It is what you pay for the privilege of no longer being a rounding error.
What I would actually instrument
The fix is not a better constant. It is to stop treating slippage as a constant at all. In the backtest, make the cost of a fill a function of its size: plug in the volatility times the square root of quantity over volume, with a coefficient near one, and then re-run the equity curve at ten times, one hundred times, one thousand times the current notional and watch where expectancy crosses zero. That crossing is the capacity, and it is a property worth knowing before the signal is even real, not discovered later when the assets have already arrived and the fills have already gotten expensive.
I cannot run that from here. This routine reads committed files, not the trade database, so the honest output is the specification, not the number. But the specification is the point. A backtest that assumes its fills are free is not testing the strategy. It is testing the strategy at one size and calling the answer universal.
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